KISSAN EDUCATION
Suppose,
Living District = Una, Himachal
Inverter's Efficiency = 95%
Battery's Efficiency = 85%
Converter Efficiency = 92%
Take Loom Solar Panel
Inverter = Microtech
consider only night backup for battery
Solution:
Total Day time consumption = 22800 Wh
Total Night-Time Consumption = 17280 Wh
Total Energy Consumption = 40080 Wh
Since Size of Plant is very high, so we have to consider only the night backup plan for optimizing
Step 1 :
Size of Inverter = Total Wattage of Appliances = Wattage * quantity = 5440 watt = 6 KW inverter
Step 2 :
Size of Battery:
Output Energy of Battery = Input energy of Inverter =(output of inverter) / (efficiency of the inverter)
= 17280 /0.95 = 18190 Wh
Energy Storage of Battery = Output Energy of Battery / DoD of Battery
= 18190 / 0.80 = 22738 Wh
Note DoD of Lead-acid Battery = 50 %
Dod of Excide Battery = 80 %
Dod of Li-ion Battery = 90 %
Let us Consider System voltage be 96V
Actual Capacity of Battery needed (Ah) = 22738vah / 96v = 237 Ah
Step 3 :
MAR | 5.67 |
APR | 5.98 |
MAY | 6.32 |
JUN | 4.86 |
JUL | 3.63 |
AUG | 3.74 |
SEP | 5.37 |
Total Panel Wattage needed = 22738 Wh/ 4.78 h = 4768 Watt = 5000 Watt Panel
For Every Inverter, there is mentioned panel capacity, how much wattage of dc panel it can handle.
We need 6Kva inverter, this inverter should handle 5000watt of the panel. If you don't get 6kva inverter for dc panel handle 5000 watts. You need to increase the size of the inverter or choose such an inverter that can handle 5000 watts of dc panel side.
note: You can search into market and dealers etc for solar inverter
For Compatibility, we take 6 Kva inverter of microteck
Capacity
|
6 kW
|
Technology
|
Sine wave, Mppt
|
Power Load
|
1 Air conditioners, Home appliances such as Light, fan, TV, Laptop, refrigerator and water motor
|
Batteries required
|
8 Nos. (150 Ah)
|
Technical
Technology
|
Sine wave
|
Solar panel current
|
46 amps
|
Solar panel voltage (voc)
|
160 V - 240 V
|
Charger technology
|
MPPT
|
Full Battery Recharge Time
|
10-12 Hrs
|
Vmp voltage = 120v - 210
Cleary This inverter can handle dc panel load 6000watt, but we need only 5000watt
Clearly, 330 Watt has the least per watt rate RS 43.
we choose panel 270 watts.
Wattage = 330W
Vmp = 37.50v
Imp = 8.5 Amp
Voc = 44v
Isc = 9.4amp
Clearly from inverter need open-circuit voltage from dc panel = 160v to 240 v
Current need = 46 Amp
Dc panel voltage range show lie between this
Total number of panel needed = 5000/330 = 15 panel (extra panel)
Total panel connection in series = 200/37.50= 5
a total panel in parallel =
5000/5*37.50 = 26.66
26.66/8.5 = 3
Hence
Total Inverter size = 6Kw
Battery size, 96, 237Ah, 96v, 120Ah ( 2 battery in parallel)
Panell = 330 Watt (5*3)
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