Skip to main content

Design of Solar Water Pump Lite version Techniques

KISSAN EDUCATION



1

2


3.


Note : This is only a lite technique to estimate design of Solar plant. It has some limitation , TDH should between 10 m to 12 m 

Q . Design a PV water Pump System, which is required to draw 250000 l or 25 Cubic meter of water every day.

ANS :  Known Data with Value :

a.Amount  of water  to be pump per day : 25m3

b.Total vertical lift = 12 m (by bottle method or sound detector)

c.Water Density = 1000kh/m3

d.Acceleration due to gravity = 9.8m/s2

e.Solar module used  = 75Wp (according to users)

f.Operating factor = 0.75

g.Pump Efficiency = 30 %

h.Mismatch factor = 0.85      // if MPPT is not used
1 is MPPT is used





Dummy Module..

Comments

Popular posts from this blog

Assignment : How to Design a Solar Power System for home

KISSAN EDUCATION www.kissanedu.com Suppose, Living District = Una, Himachal  Inverter's Efficiency = 95% Battery's Efficiency = 85% Converter Efficiency = 92% Take Loom Solar Panel Inverter = Microtech consider only night backup for battery Solution: Total Day time consumption = 22800 Wh Total Night-Time Consumption = 17280 Wh Total Energy Consumption =  40080 Wh Since Size of Plant is very high, so we have to consider only the night backup plan for optimizing Step 1 : Size of Inverter = Total Wattage of Appliances = Wattage * quantity = 5440 watt = 6 KW inverter Step 2 : Size of Battery: Output Energy of Battery = Input energy of Inverter =(output of inverter) / (efficiency of the inverter)                                           = 17280 /0.95  = 18190 Wh                      ...

Assignment 2: Design a Off Grid Solar System For Your Home

KISSAN EDUCATION www.kissanedu.com You are going to install a solar power system in our home for a total load of 800W where the required backup time of the battery is 3 hours. Optimize it. If you are living in Kolkata, West Bangla. Find out Charging Current for Battery . Take Solar Inverter, efficiency = 95% ( Luminious Inverter) Battery, efficiency = 85 % DoD = 80 % Solution :  Since , Total Wattage  = 800 W According to saftey Factor = 800 * 1.25 = 1000 Watt Step 1 : Size of inverter =  1 KW Step 2 : Size of Battery: Backup = 3 hour Back up = Total energy / Total wattage Total input energy in battery = 3 * 800 = 2400 wh Output of Battery = 2400 * efficiency = 2400 * 0.80 = 1920 wh if Voltage = 24v, Ah = 1920 / 24 = 80 Ah Charging current of battery = 10 % of Ah = 16 Amp(ideal value)  = 20 amp(real value) 24V, 80V, Step 3 : Solar irradiance in kolkata = 4.12 kwh panel size after losses = 2400 / 0.70 = 3428...